Développer puis factoriser ensuite.
A = (x+1) (x+2) + (x+2) (x+3)
B = (2x+1) + (2x+1) (x-5) + (2x+1) (x+3)
Bonsoir
A = x²+2x +x +2 +x² +3x +2x +6
A = 2x² +8x +8
A = (x+2)(x+1)+(x+3)
A = (x+2)(x+1+x+3)
A = (x+2)(2x+4)
B = (2x+1) + (2x² -10x +x -5) + (2x² +6x+x+3)
B = 2x+1 +2x² -9x -5 +2x² +7x+3
B = 4x² -1
B = (2x+1) (x-5) +(x+3)
B = (2x+1)( x-5+x+3)
B = (2x+1)(2x -2)
Développement :
A = (x+1) (x+2) + (x+2) (x+3)
A = x² +2x +x +2 +x² +3x +2x +6
A = 2x² +8x +8
Factorisation
A = (x+1) (x+2) + (x+2) (x+3) Facteur commun = (x+2)
A = (x+2) (x+1+ x+3)
A = (x+2) (2x +4)
Développement B
B= (2x+1) +( 2x+1)(x-5) + (2x +1) (x+3)
B = (2x+1) + (2x² -10x +x -5) + (2x² +6x+x+3)
B = 2x+1 +2x² -9x -5 +2x² +7x+3
B = 4x² -1
Factorisation B
B= (2x+1) +( 2x+1)(x -5) + (2x +1) (x+3) Facteur commun (2x+1)
B = (2x+1) (x -5) +(x+3)
B = (2x+1)( x-5+x+3)
B = (2x+1)(2x -2)
