Répondre :
f(x)=sinx(1+cosx) forme u v -----> u'v + v'u
u = sin x u' = cos x v = 1+ cos x v' = -sin x
f ' (x) = cos ( 1+cosx) - sinx ( sinx)
= cosx +(cosx * cos x ) - sinx ( sinx)
u = sin x u' = cos x v = 1+ cos x v' = -sin x
f ' (x) = cos ( 1+cosx) - sinx ( sinx)
= cosx +(cosx * cos x ) - sinx ( sinx)