Répondre :
a) f(1) = -100 ; g(1) = -1/6 ; h(1) = rac(12) = 2rac(3)
b)4(x-1)²-100 = 0 => 4(x-1)² = 100 => (x-1)² = 100/4 => x-1 = -5/2 => x = -3/2
=> x - 1 = 5/2 => 7/2
c) (2x-3)/(x+5) = 1 => 2x - 3 = x+5 => x = 8
et voilà
b)4(x-1)²-100 = 0 => 4(x-1)² = 100 => (x-1)² = 100/4 => x-1 = -5/2 => x = -3/2
=> x - 1 = 5/2 => 7/2
c) (2x-3)/(x+5) = 1 => 2x - 3 = x+5 => x = 8
et voilà