Répondre :
(2x-7)(5x+1) = 0
2x-7 = 0 ou 5x+1 = 0
2x = 7 5x = -1
x = [tex] \frac{7}{2} [/tex] x = [tex] \frac{-1}{5} [/tex]
(5-3x)(10+4x) = 0
5-3x = 0 ou 10+4x = 0
-3x = -5 4x = -10
x = [tex] \frac{-5}{-3} [/tex] x = [tex] \frac{-10}{4} [/tex]
2x-7 = 0 ou 5x+1 = 0
2x = 7 5x = -1
x = [tex] \frac{7}{2} [/tex] x = [tex] \frac{-1}{5} [/tex]
(5-3x)(10+4x) = 0
5-3x = 0 ou 10+4x = 0
-3x = -5 4x = -10
x = [tex] \frac{-5}{-3} [/tex] x = [tex] \frac{-10}{4} [/tex]