Répondre :
EXERCICE 63 :
A = [tex] \frac{48}{4} * \frac{6}{5} = \frac{288}{20} = \frac{72}{5} [/tex]
B = [tex]15 + \frac{2}{ \frac{50}{5} } = 15 + \frac{2}{10} = \frac{76}{5} [/tex]
C = [tex] \frac{12 - 1,2}{ \frac{72}{9} } = \frac{10,8}{8} [/tex]
A = [tex] \frac{48}{4} * \frac{6}{5} = \frac{288}{20} = \frac{72}{5} [/tex]
B = [tex]15 + \frac{2}{ \frac{50}{5} } = 15 + \frac{2}{10} = \frac{76}{5} [/tex]
C = [tex] \frac{12 - 1,2}{ \frac{72}{9} } = \frac{10,8}{8} [/tex]