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Bonsoir,
[tex]a)\ 2^{-3}=\dfrac{1}{2^3}=\dfracd{1}{8} \\\\b)\ (-5)^{-2}=\dfrac{1}{(-5)^2}=\dfrac{1}{25}\\\\c)\ 17^{-1}=\dfrac{1}{17^1}=\dfrac{1}{17} \\\\d)\ (-7)^{-2}=\dfrac{1}{(-7^2}=\dfrac{1}{49}\\\\e)\ (0, 2)^{-2}=\dfrac{1}{(-0,2)^2}=\dfrac{1}{0,04} [/tex]
[tex]f)\ (\dfrac{2}{5})=\dfrac{1}{(\dfrac{2}{5})^2}=\dfrac{1}{\dfrac{2^2}{5^2}}=\dfrac{5^2}{2^2}=\dfrac{25}{4}\\\\g)\ (\dfrac{1}{4})^{-3}=4^3=64\\\\h)\ 1^{-17}=\dfrac{1}{1^{17}}=\dfrac{1}{1}=1\\\\i)\ 1^{-18}=\dfrac{1}{1^{18}}=\dfrac{1}{1}=1\\\\k)\ (-1)^{-13}=\dfrac{1}{(-1)^{13}}=\dfrac{1}{-1}=-1\\\\l)\ (-1)^{-14}=\dfrac{1}{(-1)^{14}}=\dfrac{1}{1}=1[/tex]
[tex]a)\ 2^{-3}=\dfrac{1}{2^3}=\dfracd{1}{8} \\\\b)\ (-5)^{-2}=\dfrac{1}{(-5)^2}=\dfrac{1}{25}\\\\c)\ 17^{-1}=\dfrac{1}{17^1}=\dfrac{1}{17} \\\\d)\ (-7)^{-2}=\dfrac{1}{(-7^2}=\dfrac{1}{49}\\\\e)\ (0, 2)^{-2}=\dfrac{1}{(-0,2)^2}=\dfrac{1}{0,04} [/tex]
[tex]f)\ (\dfrac{2}{5})=\dfrac{1}{(\dfrac{2}{5})^2}=\dfrac{1}{\dfrac{2^2}{5^2}}=\dfrac{5^2}{2^2}=\dfrac{25}{4}\\\\g)\ (\dfrac{1}{4})^{-3}=4^3=64\\\\h)\ 1^{-17}=\dfrac{1}{1^{17}}=\dfrac{1}{1}=1\\\\i)\ 1^{-18}=\dfrac{1}{1^{18}}=\dfrac{1}{1}=1\\\\k)\ (-1)^{-13}=\dfrac{1}{(-1)^{13}}=\dfrac{1}{-1}=-1\\\\l)\ (-1)^{-14}=\dfrac{1}{(-1)^{14}}=\dfrac{1}{1}=1[/tex]