Répondre :
Bonsoir,
3(x + 1)² - 4 = 3(x² + 2x + 1) - 4
= 3x² + 6x + 3 - 4
= 3x² + 6x - 1
Si nous voulons factoriser :
[tex]3(x + 1)^2 - 4=(\sqrt{3})^2(x+1)^2-4\\\\3(x + 1)^2 - 4=[\sqrt{3}(x+1) ]^2-4\\\\3(x + 1)^2 - 4=[\sqrt{3}(x+1) -2][\sqrt{3}(x + 1)+2]\\\\3(x + 1)^2 - 4=(\sqrt{3}x+\sqrt{3} -2)(\sqrt{3}x + \sqrt{3}+2)[/tex]
3(x + 1)² - 4 = 3(x² + 2x + 1) - 4
= 3x² + 6x + 3 - 4
= 3x² + 6x - 1
Si nous voulons factoriser :
[tex]3(x + 1)^2 - 4=(\sqrt{3})^2(x+1)^2-4\\\\3(x + 1)^2 - 4=[\sqrt{3}(x+1) ]^2-4\\\\3(x + 1)^2 - 4=[\sqrt{3}(x+1) -2][\sqrt{3}(x + 1)+2]\\\\3(x + 1)^2 - 4=(\sqrt{3}x+\sqrt{3} -2)(\sqrt{3}x + \sqrt{3}+2)[/tex]