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To factorize the expression \( (x+1)(5-2x) - (x+1)(x+1) \), we can factor out the common factor \( (x+1) \):

\[ (x+1)(5-2x) - (x+1)(x+1) \]
\[ = (x+1)[(5-2x) - (x+1)] \]
\[ = (x+1)[5 - 2x - x - 1] \]
\[ = (x+1)(4 - 3x) \]

So, the factorized expression is \( (x+1)(4 - 3x) \).

Bonsoir;

(x+1)(5-2x)-(×+1)(x+1)​

= (x+1) ( 5-2x -x-1)

= (x+1) ( 4-3x)

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