résolu

Factoriser les expressions suivantes : A=(x−3)(2 x+ 1)+ ( x−3)(5 x−7) B=(5 x−6)(11 x+ 6)+ 8(11 x+ 6) C=(7 x 2−5)(3 x+ 9)+ (7 x−12)(3 x+ 9) D=(8 x−5)(14 x+ 5)+ (14 x+ 5) 2 E=(2 x+ 1) 2 + (2 x+ 1) F=3(2 x−3) 2 – (2 x−3) G=(x+ 4)(3 x−4) – x – 4 H=(3 x+ 7)(2 x+ 1)+ ( x−4)(−2 x−1) I=(2 x−3)(3 x+ 7) –2 x+ 3 J=(5 x−4) 2 – 5 x+ 4

Répondre :

calilou8

Bonjour

A = ( x - 3 ) ( 2x + 1) + ( x - 3 ) ( 5x - 7 )

A = ( x - 3 ) ( 2x + 1 + 5x - 7 )

B = ( 5x - 6 ) ( 11x + 6 ) + 8 ( 11x + 6 )

B = ( 11x + 6 ) ( 5x - 6 + 8 )

C = ( 7 x 2 - 5 ) ( 3x + 9 )+ ( 7x - 12 ) ( 3x + 9 )

C = ( 3x + 9 ) ( 7 x 2 - 5 + 7x - 12 )

D = ( 8x - 5 ) ( 14x + 5 ) + ( 14x + 5) 2

D = ( 14x + 5 ) ( 8x - 5 + 2 )

E = ( 2x + 1 ) 2 + ( 2x + 1)

E = ( 2x + 1 ) ( 2 + 1 )

F = 3 ( 2x - 3 ) 2 - ( 2x - 3 )

F = ( 2x - 3 ) ( 3 - 2 )

G = ( x + 4 ) ( 3x - 4 ) - x - 4

( x + 4 ) ( 3x - 4 - 1 )

H = ( 3x + 7 ) ( 2x + 1 ) + ( x - 4 ) ( -2x - 1 )

H = ( 2x + 1 ) ( 3x + 7 - x + 4 )

I = ( 2x - 3 ) ( 3x + 7 ) - 2x + 3

I = ( 2x - 3 ) ( 3x + 7 - 1 )

J = ( 5x - 4 ) 2 - 5x + 4

J = ( 5x - 4 ) ( 2 - 1 )

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