Répondre :

(2x+5)(x+1) = 2x² + 2x + 5x + 5 = 2x² + 7x + 5

(2y-1)(3y+2) = 6y² + 4y - 3y - 2 = 6y² + y - 2

(x+7)(3x-1) = 3x² - x + 21x - 7 = 3x² + 20x - 7

(2t - 3)(2t - 1) = 4t² - 2t - 6t + 3 = 4t² - 8t + 3

D'autres questions