Répondre :
(x-1/x+2)>(x+1/x-2)
(x-1/x+2)-(x+1/x-2)>0
(x-1)(x-2)/(x+2)(x-2)- (x+1)(x+2)/(x-2)(x+2)
x²-3x+2-x²-3x-2/(x-2)(x+2)
-6x/(x-2)(x+2)
[tex]x-1/x+2>x+1/x-2[/tex]
(x-1/x+2)>(x+1/x-2)
(x-1/x+2)-(x+1/x-2)>0
(x-1)(x-2)/(x+2)(x-2)- (x+1)(x+2)/(x-2)(x+2)
x²-3x+2-x²-3x-2/(x-2)(x+2)
-6x/(x-2)(x+2)